| Characteristics of a prism. Basic prism definitions. |
PAGE References to Optical Formulas Tutorial: (first reference is to edition 1 / second reference is to edition 2).
Prism definitions.
If you were
to cut that prism that you are using for the demonstration down the middle
from apex to base you would be able to place it on a protractor and measure
the angle that the two sides have to each other. That is the apical
angle. This is one of the four prism units; it is not a very useful
number by itself because the material that the prism is made from is as
important as the angle.
The deviating
angle is literally a measurement of how far the ray deviates from its path
when it passes through the prism. The deviating angle IS a useful measurement
or definition.
The amount a ray will be deviated when it passes through the prism depends on
Read the discussion on page (73 / 95-96) of the Optical Formulas Tutorial, and do the exercises at the bottom of the page.
Here are a few more for practice:
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The prism diopter and the centrad are the definitions that are currently the most useful. We use the prism diopter because we are generally using relatively weak prisms (under 15 diopters). People who design optical equipment use the centrad because it is more accurate for high power prisms. Both of these definitions are based on how far the image appears to move when the object is viewed through the prism. The prism diopter gives a good approximation of the centrad for prisms up to 15 diopters. The centrad is the most accurate measurement. [For strong prisms the prism diopter over-estimates the power of the prism; the prism diopter estimate is stronger than the more accurate centrad.]
Read through pages (74-76 / 93-98) in the Optical Formulas Tutorial, and do the exercises on those pages.
Does the 'tan' in the formulas on look familiar? If you need to, review the trigonometry part of the first module.
Here are some more exercises:
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One last aside, for those of you who are comfortable with the math above: look again at the formula for displacement:
displacement in meters x 100
diopter = ------------------------------------------------
distance away in meters
or
The point here is not for you to do the problems this way -- much better to convert displacement to cm and distance away to meters. The point is that the unit 'prism diopter' refers to a displacement that is in a 100 to 1 ratio. For every 100 units the object is from the prism the image will be displaced 1 unit. If we use inches, a one diopter prism will give one inch of image displacement for every 100 inches of distance from the prism to the object. So, if you see a problem where the units are inches (which I doubt) the formula would be
For the mathematicians/scientists out there who like to watch units, a prism diopter can be thought of as a 100/1 ratio without units, or it can be thought of has having the unit cm/m. Your choice.
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Read pages 377(bottom right)-383 in Systems for Ophthalmic Dispensing.
Do exercises 3-15 on page 384.
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